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	<title>Comments on: Calculating the second last Friday of the&#160;month</title>
	<atom:link href="http://scruss.com/blog/2009/11/07/calculating-the-second-last-friday-of-the-month/feed/" rel="self" type="application/rss+xml" />
	<link>http://scruss.com/blog/2009/11/07/calculating-the-second-last-friday-of-the-month/</link>
	<description>tig - you&#039;re het!</description>
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		<title>By: scruss</title>
		<link>http://scruss.com/blog/2009/11/07/calculating-the-second-last-friday-of-the-month/comment-page-1/#comment-135017</link>
		<dc:creator>scruss</dc:creator>
		<pubDate>Tue, 10 Nov 2009 00:15:36 +0000</pubDate>
		<guid isPermaLink="false">http://scruss.com/blog/?p=4870#comment-135017</guid>
		<description>Why spend 10 minutes every two years writing entries manually when you can spend all morning writing a program to do it?</description>
		<content:encoded><![CDATA[<p>Why spend 10 minutes every two years writing entries manually when you can spend all morning writing a program to do it?</p>
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		<title>By: Ken</title>
		<link>http://scruss.com/blog/2009/11/07/calculating-the-second-last-friday-of-the-month/comment-page-1/#comment-135000</link>
		<dc:creator>Ken</dc:creator>
		<pubDate>Mon, 09 Nov 2009 12:26:20 +0000</pubDate>
		<guid isPermaLink="false">http://scruss.com/blog/?p=4870#comment-135000</guid>
		<description>How about doing it by hand ?.

2 years worth is only 24 manual entries, and you could put a reminder on the 23rd one to create 24 more.</description>
		<content:encoded><![CDATA[<p>How about doing it by hand ?.</p>
<p>2 years worth is only 24 manual entries, and you could put a reminder on the 23rd one to create 24 more.</p>
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		<title>By: Thomas</title>
		<link>http://scruss.com/blog/2009/11/07/calculating-the-second-last-friday-of-the-month/comment-page-1/#comment-134987</link>
		<dc:creator>Thomas</dc:creator>
		<pubDate>Sun, 08 Nov 2009 22:11:54 +0000</pubDate>
		<guid isPermaLink="false">http://scruss.com/blog/?p=4870#comment-134987</guid>
		<description>OK, use MOD then: DATE(year,month+1,1)-MOD(WEEKDAY(DATE(year,month+1,1)),7)-8</description>
		<content:encoded><![CDATA[<p>OK, use MOD then: DATE(year,month+1,1)-MOD(WEEKDAY(DATE(year,month+1,1)),7)-8</p>
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		<title>By: scruss</title>
		<link>http://scruss.com/blog/2009/11/07/calculating-the-second-last-friday-of-the-month/comment-page-1/#comment-134964</link>
		<dc:creator>scruss</dc:creator>
		<pubDate>Sat, 07 Nov 2009 23:37:47 +0000</pubDate>
		<guid isPermaLink="false">http://scruss.com/blog/?p=4870#comment-134964</guid>
		<description>Yes, that seems to work, thanks - but ew, -IF(...) syntax ...</description>
		<content:encoded><![CDATA[<p>Yes, that seems to work, thanks &#8211; but ew, -IF(&#8230;) syntax &#8230;</p>
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		<title>By: Thomas</title>
		<link>http://scruss.com/blog/2009/11/07/calculating-the-second-last-friday-of-the-month/comment-page-1/#comment-134963</link>
		<dc:creator>Thomas</dc:creator>
		<pubDate>Sat, 07 Nov 2009 21:45:36 +0000</pubDate>
		<guid isPermaLink="false">http://scruss.com/blog/?p=4870#comment-134963</guid>
		<description>Wouldn&#039;t DATE(B12,C12+1,1)-IF(WEEKDAY(DATE(B12,C12+1,1),1) &gt; 6, 0, WEEKDAY(DATE(B12,C12+1,1),1))-8 do the trick in Excel?</description>
		<content:encoded><![CDATA[<p>Wouldn&#8217;t DATE(B12,C12+1,1)-IF(WEEKDAY(DATE(B12,C12+1,1),1) &gt; 6, 0, WEEKDAY(DATE(B12,C12+1,1),1))-8 do the trick in Excel?</p>
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